On Tue, 18 Jan 2005, Richard Henderson wrote:
On Tue, Jan 18, 2005 at 03:38:33PM -0600, Chris Lattner wrote:Note that this is severely slow down your code if it is FP intensive, but it will produce correct results.
Modulo double rounding of course.
Care to elaborate?
double X = .. float F1 = (float)(float)D; float F2 = (float)(double)(float)D; float F3 = (float)D;
Aren't F1, F2, and F3 identical?
-Chris
-- http://nondot.org/sabre/ http://llvm.cs.uiuc.edu/
