Re: gcc 3.3 / i386 / -O2 question

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Michael Matz wrote:

While it's true that with signed arithmetic we are allowed to simply
break, such behaviour can (and in this case indeed does) point out a real
problem in the optimizers, so its often a bit too hasty to ignore a
problem just because the source code is not totally conformant.

Interesting, though to be fair, David a couple of times said that it would be a good idea to try this code again with unsigned :-)


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