> -----Original Message-----
> From: binutils-owner On Behalf Of bserdar
> Sent: 15 October 2004 19:27
> > 80485b3: e8 00 00 00 00 call 80485b8 <X::f()+0xc>
> > 80485b8: 5b pop %ebx
> > 80485b9: 81 c3 5c 12 00 00 add $0x125c,%ebx
>
> With pop ebx, it pops the eip at that instruction to ebx. I'm
> guessing it'll use ebx as a base pointer to data (or code?)
> from this point on. You can verify this guess by accessing
> some global variables from within X::f() and see whether it
> uses ebx-relative access.
>
Oh blimey, I didn't spot that. Yes, of course that's what it's doing.
Please ignore my previous post, I would now assume that the -r flag will in
fact show that no reloc is applied nor needed on that instruction.
cheers,
DaveK
--
Can't think of a witty .sigline today....
