hi Eljay,
I understand the solution given by u and its workign is also fine . but could not understand why this is not working
thanks
ankit
--- Krzysztof.Wisniowski@xxxxxxxxxxx wrote:
Hallo *, Here's the problem:
unsigned int ui = 4294967295; //2^16-1
Actually, that's 2^32-1.
unsigned long long uL; //8-byte variable
uL = ui << 16;
You're asking that a 32 bit value (ui) be left shifted 16 places. This means that the 16 high bits will be discarded. The result of that left shift will then be assigned to uL.
I believe that another solution would be to write it as: uL = (unsigned long long)ui << 16;
this casts ui to an unsigned long long - so we're now asking that a 64 bit value be left shifted 16 places - and no bits will be lost. Consequently uL will contain the value you expect.
Get the picture ?
Cheers, Rob
