RE: Problem with implicit conversion (GCC 3.4.1)

[lrtaylor@xxxxxxxxxx]

Well, you've declared a <= operator that can compare to BasisF objects,
but you're trying to compare a BasisF object with a double, which you
haven't created an operator for:

min(t,2.0)  -> ((t) <= (2.0) ? (t) > (2.0))

So, in your min macro, you are trying to compare the object t with the
double 2.0.  You don't have an operator for that.

Thanks,
Lyle

-----Original Message-----
From: gcc-help-owner@xxxxxxxxxxx [mailto:gcc-help-owner@xxxxxxxxxxx] On
Behalf Of Boris von Loesch
Sent: Thursday, August 26, 2004 3:55 AM
To: gcc-help@xxxxxxxxxxx
Subject: Problem with implicit conversion (GCC 3.4.1)

Hello,

I have written a program that compiles just fine with GCC 3.3. With
GCC 3.4.1 it results in this error:

g++ -O0 -g3 -Wall -c -oTestp.o ../Testp.c
../Testp.c: In function `int main()':
../Testp.c:26: error: no match for 'operator<=' in 't <= 2.0e+0'

Please help me, I have no idea where the problem is.

Here is the code:

template <class T> class BasisF;
	
template <class T> inline bool operator<=(const BasisF<T> &a, const
BasisF<T> &b){return a.x <= b.x;}

template<class T> class BasisF{

public:
	T x;
	BasisF(const T &_x = T()): x(_x){}
	BasisF(const BasisF &_b): x(_b.x){}
	~BasisF(){}
	BasisF& operator= (const T &_x){
		 x(_x);
		 return *this;
	}
	friend bool operator<=<>(const BasisF &a, const BasisF &b);
	};

#define min(a,b) ((a) <= (b) ? (a) : (b))

int main(){
	BasisF<double> t(1);
	if (min(t,2.0)<=0) return 1;
	return 0;
}

Regards,
Boris