hi
well i want to understand how assembler treats
pointers?
my code is:
1 #include<inttypes.h>
2
3
4 int main()
5 {
6 uint8_t
a[8]={1,2,3,4,5,6,7,8},b[8]={0,0,0,0,0,0},i;
7 uint8_t *m,*m1;
8
9 m=a;
10 m1=b; //i have pointed m1 to b
11 for(i=0;i<8;i++)
12 printf("%d ",a[i]);
13 printf("\n");
14 asm("movq (%1), %%mm0 \n"
15 "movq %%mm0, (%0) \n"
16 :"=r"(m1)
17 :"r"(m)
18 );
19
20 for(i=0;i<8;i++)
21 printf("%d ",b[i]);
22 return 0;
23 }
well this problem is not solved yet. because when i
display b array then it prints all 0's. according to
me since i have initialised this m1 pointer then by b
then b whould have all the values which i have moved
some have advised me to use arrays here as constraint
but i want to use pointers. i am using r constraint
and it says it says that m1 will use a register (i
guess there is no problem in that)
what is the complete problem HOW THIS ASSEMBLER IS
TREATING THIS POINTER m1?
thanks
ankit jain
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