Hi,
I get some warnings with following code:
__int64 hash;
hash=(hash<<1) & 0x7FFFFFFFFFFFFFFFL;
The warnings tell me that the constant is too long for the datatype of "hash". But when I count the digits of 0x7FFFFFFFFFFFFFFFL there are exactly 16 which are equal to 64 bit. It doesn't helps either when I change the datatype from __int64 to (unsigned) long long, so what could be the reason for this warning?
Michael
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