Re: template parameters cannot be friends

[Eljay Love-Jensen <eljay@xxxxxxxxx>]

Hi Naje,

>i do not need put method draw in Window's children.

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#include <iostream>

using namespace std;

class Window
{
public:
    void Draw() const
    {
        cout << "Window::Draw" << endl;
    }
};

class BoxWindow : private Window
{
public:
    using Window::Draw;
};

template <typename T>
void Draw(T const& object)
{
    object.Draw();
}

int main()
{
    BoxWindow box;
    Draw(box);
}
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HTH,
--Eljay