On Mon, Mar 01, 2004 at 06:53:47PM -0800, Jeffrey Holle wrote:
> More info:
> I have successfully used my templated function when I do not make the
> methods that it uses private. This avoids the friend issues that I'm
> having problems with.
>
> I do not want to keep my app this way. There are specific reasons I
> want to restrict access to these methods, so I'd really like to know why
> friend functions don't work.
>
> Jeffrey Holle wrote:
> >I use gcc v3.3.
> >I'm developing an application in which I want to restrict access to a
> >member function to everything but 1 function.
> >
> >I'm attempting to accomplish this by making the method private and my
> >function a friend, but failing.
> >
> >The synopsis of the function is:
> > template<class T1> void putNamespace(const string& name, T1& object);
> >
> >I attempt to define this function has a friend of CParameter with the
> >following in the public definition area of this class.
> > friend void putNamespace(const string& name, CParameter& object);
> >
> >I've tried to indicate what this function actually is (a template), but
> >run into compiler errors.
> >
> >It compiled the shared library that I'm defining it in, but when I
> >attempt to compile a client that uses it like:
> > putNamespace("std",myParameter);
> >I get errors associated with putNamespace attempting to a private method
> >of CParameter, which it does!
> >
> >I've backed off from the template as an experiment. In defining
> >putNamespace to take a second parameter of "CParameter", I get these
> >compilation errors in compiling my shared library.
> >
> >Can anybody tell me what I'm doing wrong?
Please don't try to paraphrase, just post example code which exhibits the
error plus the command line incl. options plus the errors GCC produced. It's
way easier to provide help this way.
On to the problem. Try this:
template <class T> void my_fun (const string&, T&);
class A {
friend void my_fun<> (const string&, A&);
void call_me () { };
};
template <class T>
void my_fun (const string& str, T& obj)
{
obj.call_me ();
}
Note, however, this will only work if the function is declared in the
nearest enclosing namespace scope of class A.
PS: Don't top-post. TIA.
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