Hi all!
How can I find out the precision (mantissa length) of a floating point
number in i386 architecture?
I don't understand the output the following program (why long double and
double have the same mantissa length?)
#include <iostream>
using namespace std;
int main() {
float c3;
double c2;
long double c1;
c3=1.1234567890123456789012345678901234567890123456789012345678901234567890;
c2=1.1234567890123456789012345678901234567890123456789012345678901234567890;
c1=1.1234567890123456789012345678901234567890123456789012345678901234567890;
cout.precision(50);
cout << "long double c1 = " << c1 << " " << sizeof(c1) << endl;
cout << " double c2 = " << c2 << " " << sizeof(c2) << endl;
cout << " float c3 = " << c3 << " " << sizeof(c3) << endl;
}
output:
long double c1 = 1.1234567890123456912476740399142727255821228027344 12
double c2 = 1.1234567890123456912476740399142727255821228027344 8
float c3 = 1.12345683574676513671875 4
