Re: Class casting

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Justin Miller wrote:
Interestingly enough, if you did this:

int main() {
        B b;
        C* c = new C(b);
}

It will compile and work as expected. The constructor wants an A, a B is
an A, so everything is fine.

Why one needs to declare the B first, rather than instantiating the
temporary as in the code below, I have no idea. Can anyone shed some
light on this?
class C{
    public:
    C(A& a) : initialize....{do Stuff;}

The 'B ()' part of 'C (B ())' cannot bind to a non-const reference.

nathan
--
Nathan Sidwell    ::   http://www.codesourcery.com   ::     CodeSourcery LLC
         The voices in my head said this was stupid too
nathan@xxxxxxxxxxxxxxxx    ::     http://www.planetfall.pwp.blueyonder.co.uk



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