What is it testing for? prep #cleanup cp $FONT1 $FONTDIR #put 1 font into fontdir $FCCACHE $FONTDIR #create a cache for that fontdir cat $FONTDIR/.uuid #print the contents of the .uuid file (why?) $FCCACHE -r $FONTDIR #re-create a cache for that fontdir uuid=`cat $FONTDIR/.uuid` #get the contents of the .uuid file ls $CACHEDIR/$uuid* if [ $? != 0 ]; then #verify that a UUID-based cache subdir exists echo "*** Test failed: $TEST" echo "No cache for $uuid" ls $CACHEDIR exit 1 fi n=`ls -1 $CACHEDIR/*cache-* | wc -l` #count the number of cache subdirs if [ $n != 1 ]; then #verify that only one cache subdir exists echo "*** Test failed: $TEST" echo "Unexpected cache was created" ls $CACHEDIR exit 1 fi Why is it checking that only one cache subdir exists? The second invocation of fc-cache, with -r, deletes the old cache and creates a new one. I can't see why this test expects that only one cache will exist after this.
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