Re: Need help with incompatible pointer types on i686

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* Orion Poplawski:

> It seems that numpy is defining a uint32_t type as long unsigned int
> on i686, while glibc(?) is defining it as unsigned int.  Now what
> puzzles me a little is that on i686 aren't these both 4-byte integers
> and no not incompatible at all?

The types int and long are distinct according to C rules.

The problem seems to be in h5py/api_types_ext.pxd:

from numpy cimport int8_t, uint8_t, int16_t, uint16_t, int32_t, uint32_t, int64_t, uint64_t

I think it should use the types from <stdint.h> instead, at least in the
global scope.  For certain Numpy functions, it may be required to
reference them as numpy.uint32_t etc.

Thanks,
Florian
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