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Dear dm-crypt developer,
Hi, I'm Yoo-Seung Won who works at Nanyang Technological University.
I use your open source to encrypt some file or disks.
My question is below.
I want to encrypt single file using some commands as below.
========================================================================================================================
cryptsetup --verbose --cipher=aes-ecb --key-size=128 --key-file=/dev/example/aes_key.bin open --type=plain /dev/example/aes_data.bin enc
I know the meaning of each commands because I read the document.
aes_key.bin only has 16 bytes 0x00 (That is, 0x00 0x00 0x00 0x00 0x00 0x00 0x00 0x00 0x00 0x00 0x00 0x00 0x00 0x00 0x00 0x00)
I means this file only consists of hexa.
And,
aes_data.bin has 0x800 bytes 0x00
========================================================================================================================
Finally, I got the enc in /dev/mapper
I opened the enc file. There is only 0x600 bytes. (I expected the 0x800 bytes because I use the AES-ECB)
Also, 0x600 bytes are composed of 96 16bytes (14 0f 0f 10 11 b5 22 3d 79 5 77 17 ff d9 ec 3a).
I expected that 128 16bytes (66 E9 4B D4 EF 8A 2C 3B 88 4C FA 59 CA 34 2B 2E) because I used the all zero keys and all zero data
Encrypted data = "" / key)
66 E9 4B D4 EF 8A 2C 3B 88 4C FA 59 CA 34 2B 2E = AES(00, 00, 00, 00, 00, 00, 00, 00, 00, 00, 00, 00, 00, 00, 00, 00 / 00, 00, 00, 00, 00, 00, 00, 00, 00, 00, 00, 00, 00, 00, 00, 00)
I think that the encrypted data is wrong and file size also is wrong.
If you don't mind, could you tell me what I miss?
Best Wishes,
Yoo-Seung.
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