Hello, I'm wondering how the --offset works in cryptsetup? For exemple, Why this doesn't work: root@ubu:/tmp# losetup -o 20 /dev/loop0 /tmp/25M root@ubu:/tmp# echo "pass" | cryptsetup -c aes create 25 /dev/loop0 root@ubu:/tmp# mke2fs /dev/mapper/25 <...> root@ubu:/tmp# cryptsetup remove 25 root@ubu:/tmp# losetup -d /dev/loop0 root@ubu:/tmp# losetup /dev/loop0 /tmp/25M root@ubu:/tmp# echo "pass" | cryptsetup -c aes -o 20 create 25 /dev/loop0 root@ubu:/tmp# mount -t ext2 /dev/mapper/25 /mnt/ mount: wrong fs type, bad option, bad superblock on /dev/mapper/25, missing codepage or other error In some cases useful info is found in syslog - try dmesg | tail or so In the first case, I jump 20 bytes in the creation of the loop, and use it with cryptsetup. In the second case, I use the loop from the beginning, then I jump 20 bytes before doing any encryption. So the 21byte should be the same? So why this doesn't work? how ths -o option works? Am I missing something? thanks Eurolines : Voyagez au meilleur prix : http://www.alinto.com/pub/ --------------------------------------------------------------------- dm-crypt mailing list - http://www.saout.de/misc/dm-crypt/ To unsubscribe, e-mail: dm-crypt-unsubscribe@xxxxxxxx For additional commands, e-mail: dm-crypt-help@xxxxxxxx