On Fri, 2015-06-12 at 09:55 +0800, Koro Chen wrote: > On Thu, 2015-06-11 at 09:03 +0200, Paul Bolle wrote: > > (What does negating a bool twice do?) > > > Because bool actually can be unsigned char, although actually in this > driver, the caller always passes "true" or "false" to this function. bool is _Bool in the kernel (see include/linux/types.h). So whenever you see a bool in the kernel you can assume it's either 0 or 1. Are there any cases where this conveniently simple rule doesn't hold? But here the discussion is moot, because as you say, the function will only be passed false or true so we know "enable" is either 0 or 1 and double negating will do nothing. > Do you think if this is the case, should I still need to do !!? So you should not, as it's confusing at best. Thanks, Paul Bolle -- To unsubscribe from this list: send the line "unsubscribe devicetree" in the body of a message to majordomo@xxxxxxxxxxxxxxx More majordomo info at http://vger.kernel.org/majordomo-info.html
