Re: [PATCH v7 1/1] pwm: imx27: workaround of the pwm output bug when decrease the duty cycle

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On 10/4/24 10:58 PM, Uwe Kleine-König wrote:

[...]

@@ -263,7 +266,77 @@ static int pwm_imx27_apply(struct pwm_chip *chip, struct pwm_device *pwm,
  		pwm_imx27_sw_reset(chip);
  	}
- writel(duty_cycles, imx->mmio_base + MX3_PWMSAR);
+	/*
+	 * This is a limited workaround. When the SAR FIFO is empty, the new
+	 * write value will be directly applied to SAR even the current period
+	 * is not over.
+	 *
+	 *           ─────────────────────┐
+	 * PWM OUTPUT                     │
+	 *                                └─────────────────────────
+	 *
+	 *           ┌──────────────────────────────────────────────┐
+	 * Counter   │       XXXXXXXXXXXXXX                         │
+	 *           └──────────────────────────────────────────────┘
+	 *                   ▲            ▲
+	 *                   │            │
+	 *                 New SAR      Old SAR
+	 *
+	 *           XXXX  Errata happen window

Hmm, ok, so SAR is the register value that implements the duty cycle
setting. And if a new SAR is written, it is directly applied to the
hardware and this way it can happen (if SAR_new < counter < SAR_old)
that no falling edge happens in the current period. Right?

Yes

If so, I think the depicted PWM output is misleading. I'd describe and
picture it as follows:

Why not simply duplicate the ERRATA description for iMX8M Nano MX8MN_0N14Y errata sheet ?

"
ERR051198:
PWM: PWM output may not function correctly if the FIFO is empty when a new SAR value is programmed

Description:
When the PWM FIFO is empty, a new value programmed to the PWM Sample register (PWM_PWMSAR) will be directly applied even if the current timer period has not expired.

If the new SAMPLE value programmed in the PWM_PWMSAR register is less than the previous value, and the PWM counter register (PWM_PWMCNR) that contains the current COUNT value is greater than the new programmed SAMPLE value, the current period will not flip the level. This may result in an output pulse with a duty cycle of 100%.
"

That is very clear to me.

	/*
	 * At each clock tick the hardware compares the SAR value with
	 * the current counter. If they are equal the output is changed
	 * to the inactive level.

I would skip this ^ part unless you can surely say the IP works exactly that way because you checked the RTL.

As a new SAR value is applied
	 * immediately to the currently running period, it can happen
	 * that no falling edge happens in a period and so the output is
	 * active for a whole period. Consider a change from
          *     ________
	 *    /        \______/
          *    ^      *        ^
	 * to
          *     ____
	 *    /    \__________/
          *    ^               ^
	 *
	 * where SAR is written at the time marked by *. The counter
	 * didn't reach the old (bigger) value because it was changed
	 * before the counter reached that value and when the new value
	 * becomes active it is already lower than the current counter
	 * and so doesn't trigger either while the counter continues to
	 * grow. So the resulting waveform looks as follows:
	 *
          *     ________        ____________________
	 *    /        \______/                    \__________/
          *    ^               ^      *        ^               ^
	 *    |<-- old SAR -->|               |<-- new SAR -->|
	 *
	 * that is the output is active for a whole period.

The ascii/infographics is nice and would be good to keep, but regarding the description, frankly, the NXP errata description says the same thing in fewer words :)

	 */

+	 *
+	 * If the new SAR value is less than the old one, and the counter is
+	 * greater than the new SAR value (see above diagram XXXX), the current
+	 * period will not flip the level. This will result in a pulse with a
+	 * duty cycle of 100%.
+	 *
+	 * Check new SAR less than old SAR and current counter is in errata
+	 * windows, write extra old SAR into FIFO and new SAR will effect at
+	 * next period.
+	 *
+	 * Sometime period is quite long, such as over 1 second. If add old SAR
+	 * into FIFO unconditional, new SAR have to wait for next period. It
+	 * may be too long.
+	 *
+	 * Turn off the interrupt to ensure that not IRQ and schedule happen
+	 * during above operations. If any irq and schedule happen, counter
+	 * in PWM will be out of data and take wrong action.
+	 *
+	 * Add a safety margin 1.5us because it needs some time to complete
+	 * IO write.
+	 *
+	 * Use __raw_writel() to minimize the interval between two writes to
+	 * the SAR register to increase the fastest PWM frequency supported.
+	 *
+	 * When the PWM period is longer than 2us(or <500kHz), this workaround
+	 * can solve this problem. No software workaround is available if PWM
+	 * period is shorter than IO write.
+	 */
+	c = clkrate * 1500;
+	do_div(c, NSEC_PER_SEC);
+
+	local_irq_save(flags);
+	val = FIELD_GET(MX3_PWMSR_FIFOAV, readl_relaxed(imx->mmio_base + MX3_PWMSR));
+
+	if (duty_cycles < imx->duty_cycle) {
+		if (state->period < 2000) { /* 2000ns = 500 kHz */
+			/* Best effort attempt to fix up >500 kHz case */
+			udelay(6); /* 2us per FIFO entry, 3 FIFO entries written => 6 us */

I don't understand the motivation to wait here. Wouldn't it be better to
write the old value 3 - val times and not sleep?

No, because you would overflow the FIFO, see:

137fd45ffec1 ("pwm: imx: Avoid sample FIFO overflow for i.MX PWM version2")

Or busy loop until
MX3_PWMSR_FIFOAV becomes 0?

Do we really want a busy wait here if we can avoid it ?

We can do udelay(3 * state->period / 1000); so faster PWMs would wait shorter.

The delay is here to basically wait until the FIFO is surely empty and has space for 3 consecutive writes (see the commit above wrt. FIFO overflow).

[...]




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