On 6/27/22 15:17, Heikki Krogerus wrote: > Hi, > > On Fri, Jun 24, 2022 at 05:54:11PM +0200, Fabrice Gasnier wrote: >> +static int ucsi_stm32g0_probe(struct i2c_client *client, const struct i2c_device_id *id) >> +{ >> + struct device *dev = &client->dev; >> + struct ucsi_stm32g0 *g0; >> + int ret; >> + >> + g0 = devm_kzalloc(dev, sizeof(*g0), GFP_KERNEL); >> + if (!g0) >> + return -ENOMEM; >> + >> + g0->dev = dev; >> + g0->client = client; >> + init_completion(&g0->complete); >> + i2c_set_clientdata(client, g0); >> + >> + g0->ucsi = ucsi_create(dev, &ucsi_stm32g0_ops); >> + if (IS_ERR(g0->ucsi)) >> + return PTR_ERR(g0->ucsi); >> + >> + ucsi_set_drvdata(g0->ucsi, g0); >> + >> + /* Request alert interrupt */ >> + ret = request_threaded_irq(client->irq, NULL, ucsi_stm32g0_irq_handler, IRQF_ONESHOT, >> + dev_name(&client->dev), g0); >> + if (ret) { >> + dev_err_probe(dev, ret, "request IRQ failed\n"); >> + goto destroy; >> + } >> + >> + ret = ucsi_register(g0->ucsi); >> + if (ret) { >> + dev_err_probe(dev, ret, "ucsi_register failed\n"); >> + goto freeirq; >> + } > > If there isn't UCSI firmware, then ucsi_register() will always safely > fail here, right? Hi Heikki, Yes, in such a case, the first i2c read (UCSI_VERSION) in ucsi_register() will return an error and safely fail here. Thanks for reviewing, Best Regards, Fabrice > > >> + return 0; >> + >> +freeirq: >> + free_irq(client->irq, g0); >> +destroy: >> + ucsi_destroy(g0->ucsi); >> + >> + return ret; >> +} > > > thanks, >