> + - big-endian : If this property is absent, the native endian mode will > + be in use as default, or the big endian mode will be in use > + for all the device registers. Native endian is meaningless. If a CPU supports both BE and LE, there is no native endianness. The endianness of the kernel is dynamic while the endianness of registers in HW is fixed. Just choose an endianness to assume by default (presumably little). That way this describes the HW and always works with a kernel of arbitrary endianness. Thanks, Mark. -- To unsubscribe from this list: send the line "unsubscribe devicetree" in the body of a message to majordomo@xxxxxxxxxxxxxxx More majordomo info at http://vger.kernel.org/majordomo-info.html
