On Sat, Sep 10, 2016 at 3:29 AM, Fabio Estevam <festevam@xxxxxxxxx> wrote:
> On Fri, Sep 9, 2016 at 6:45 PM, Jagan Teki <jagannadh.teki@xxxxxxxxx> wrote:
>
>> +&iomuxc {
>> + pinctrl_flexcan1: flexcan1grp {
>> + fsl,pins = <
>> + MX6QDL_PAD_KEY_ROW2__FLEXCAN1_RX 0x1b020
>> + MX6QDL_PAD_KEY_COL2__FLEXCAN1_TX 0x1b020
>
> In the previous version you had "0x80000000", which means: use the pad
> value that comes from the bootloader.
>
> Does your bootloader configure the CAN pins? If not, then it should be
> 1b0b0, which is the POR value of register
> IOMUXC_SW_PAD_CTL_PAD_KEY_ROW2.
>
> To confirm, you can do this in your bootloader:
>
> => md.l 20E05DC 1
> 020e05dc: 0001b0b0
>
> and see if returns 1b0b0 or 1b020.
Yeah, I got 1b0b0
U-Boot > md.l 20E05DC 1
020e05dc: 0001b0b0
thanks!
--
Jagan Teki
Free Software Engineer | Amarula Solutions
U-Boot, Linux | Upstream Maintainer
Hyderabad, India.
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