The comment by Dave brought me back to check what a change of
a factor of 10 does to the throughput in TFRC.
RFC 3448 gives in section 8 the following alternative format
of the throughput equation (which is directly responsible for
the alllowed sending rate X):
s
X = --------
R * f(p)
This shows that the dependence is reciprocal. Thus using an RTT
which differs by a factor of 10 to account for in-stack processing
results an a throughput reduction of factor 10.
In other words, 90 Mbits/sec becomes 9 Mbits/sec.
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