Hi dash folks, we stumbled over a little curiosity in dash's behavior when you combine a variable assignment within an export statement with command sub- stitution. The following works fine in bash: $ export foo=$(echo foo bar) $ echo $foo foo bar dash, however, applies field splitting and thus takes `bar` as a second variable name: $ export foo=$(echo foo bar) $ echo $foo foo which can easily be fixed by adding double quotes: $ export foo="$(echo foo bar)" $ echo $foo foo bar I know bash shouldn't be the reference so I had a look at [1]. It states: "If a command substitution occurs inside double-quotes, field splitting and pathname expansion shall not be performed on the results of the substitution." Which one could read as field splitting should take place if you don't supply double quotes. But in present shells variable assignments seem to be an exception. And even dash doesn't apply field splitting on a simple assignment: $ foo=$(echo foo bar) $ echo $foo foo bar That's at least inconsistent and, IMO, the export statement should have the same semantics (i.e. not requiring double quotes) as things can get quite nasty if you think of evaluations like: $ export foo=$(echo bar bar=foo) $ echo $foo bar $ echo $bar foo Best regards, Nico [1] http://pubs.opengroup.org/onlinepubs/9699919799/utilities/V3_chap02.html#tag_18_06_03 -- To unsubscribe from this list: send the line "unsubscribe dash" in the body of a message to majordomo@xxxxxxxxxxxxxxx More majordomo info at http://vger.kernel.org/majordomo-info.html