On Thu, Oct 07, 2004 at 02:39:24PM -0400, Ed L Cashin wrote: > > 5) Node A completes writing inode 23. This consists of: > > A) Writing the new block to Disk 0 > > A) Writing the new parity block to Disk 2 > > 6) Node A completes writing inode 24. This consists of: > > That's node B if I am following you correctly. Yep. And steps 5 and 6 should have an A and B step instead of two A steps. I never was good at using the alphabet. > ... > It sounds like it would be slow. Maybe not in a situation with > reader-writer locks, where writes were infrequent, though. Yes, it would be slow. Reader-writer locks would help some when you're running in degraded mode after losing a disk. But in normal operation, you wouldn't need to lock stripes to read from them -- so all locking requests would be for the writer version of the lock. -- Ken Preslan <kpreslan@xxxxxxxxxx>
