On Wed 20-10-21 17:21:33, Vasily Averin wrote: > On 20.10.2021 15:41, Michal Hocko wrote: > > On Wed 20-10-21 15:13:46, Vasily Averin wrote: > >> ToDo: should we keep task_is_dying() in mem_cgroup_out_of_memory() ? > >> > >> Signed-off-by: Vasily Averin <vvs@xxxxxxxxxxxxx> > >> --- > >> mm/memcontrol.c | 20 +++++++------------- > >> 1 file changed, 7 insertions(+), 13 deletions(-) > >> > >> diff --git a/mm/memcontrol.c b/mm/memcontrol.c > >> index 6da5020a8656..74a7379dbac1 100644 > >> --- a/mm/memcontrol.c > >> +++ b/mm/memcontrol.c > >> @@ -239,7 +239,7 @@ enum res_type { > >> iter != NULL; \ > >> iter = mem_cgroup_iter(NULL, iter, NULL)) > >> > >> -static inline bool should_force_charge(void) > >> +static inline bool task_is_dying(void) > >> { > >> return tsk_is_oom_victim(current) || fatal_signal_pending(current) || > >> (current->flags & PF_EXITING); > >> @@ -1575,7 +1575,7 @@ static bool mem_cgroup_out_of_memory(struct mem_cgroup *memcg, gfp_t gfp_mask, > >> * A few threads which were not waiting at mutex_lock_killable() can > >> * fail to bail out. Therefore, check again after holding oom_lock. > >> */ > >> - ret = should_force_charge() || out_of_memory(&oc); > >> + ret = task_is_dying() || out_of_memory(&oc); > > > > Why are you keeping the task_is_dying check here? IIRC I have already > > pointed out that out_of_memory already has some means to do a bypass > > when needed. > > It was a misunderstanding. Sorry if I made you confused. > I've been waiting for your final decision. > > I have no good arguments "pro" or strong objection "contra". > However, I prefer to keep task_is_dying() so as not to touch other tasks unnecessarily. One argument for removing it from here is the maintainability. Now you have a memcg specific check which is not in sync with the oom. E.g. out_of_memory does task_will_free_mem as the very first thing. You are also automatically excluding oom killer for cases where that might make a sense. -- Michal Hocko SUSE Labs