Michal noted that a cpuset's effective_cpus can be a non-empy mask, but
because of the masking done with housekeeping_cpumask(HK_FLAG_DOMAIN)
further down the line, we can still end up with an empty cpumask being
passed down to partition_sched_domains_locked().
Do the proper thing and don't just check the mask is non-empty - check
that its intersection with housekeeping_cpumask(HK_FLAG_DOMAIN) is
non-empty.
Fixes: cd1cb3350561 ("sched/topology: Don't try to build empty sched domains")
Reported-by: Michal Koutný <mkoutny@xxxxxxxx>
Signed-off-by: Valentin Schneider <valentin.schneider@xxxxxxx>
---
kernel/cgroup/cpuset.c | 8 +++++++-
1 file changed, 7 insertions(+), 1 deletion(-)
diff --git a/kernel/cgroup/cpuset.c b/kernel/cgroup/cpuset.c
index c87ee6412b36..e4c10785dc7c 100644
--- a/kernel/cgroup/cpuset.c
+++ b/kernel/cgroup/cpuset.c
@@ -798,8 +798,14 @@ static int generate_sched_domains(cpumask_var_t **domains,
cpumask_subset(cp->cpus_allowed, top_cpuset.effective_cpus))
continue;
+ /*
+ * Skip cpusets that would lead to an empty sched domain.
+ * That could be because effective_cpus is empty, or because
+ * it's only spanning CPUs outside the housekeeping mask.
+ */
if (is_sched_load_balance(cp) &&
- !cpumask_empty(cp->effective_cpus))
+ cpumask_intersects(cp->effective_cpus,
+ housekeeping_cpumask(HK_FLAG_DOMAIN)))
csa[csn++] = cp;
/* skip @cp's subtree if not a partition root */
--
2.22.0
