Hello guys, how does one estimate number of chunks for erasure coded pool ( k = ? ) ? I see that number of m chunks determines the pool’s resiliency, however I did not find clear guideline how to determine k. Red Hat states that they support only the following combinations: k=8, m=3 k=8, m=4 k=4, m=2 without any rationale behind them. The table is taken from https://access.redhat.com/documentation/en-us/red_hat_ceph_storage/3/html/storage_strategies_guide/erasure_code_pools. Thanks! Regards, Martin
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