Re: Size of cluster

[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]

 



Hi,

Am 09.08.21 um 12:56 schrieb Jorge JP:

> 15 x 12TB = 180TB
> 8 x 18TB = 144TB

How are these distributed across your nodes and what is the failure
domain? I.e. how will Ceph distribute data among them?

> The raw size of this cluster (HDD) should be 295TB after format but the size of my "primary" pool (2/1) in this moment is:

A pool with a size of 2 and a min_size of 1 will lead to data loss.

> 53.50% (65.49 TiB of 122.41 TiB)
> 
> 122,41TiB multiplied by replication of 2 is 244TiB, not 295TiB.
> 
> How can use all size of the class?

If you have 3 nodes with each 5x 12TB (60TB) and 2 nodes with each 4x
18TB (72TB) the maximum usable capacity will not be the sum of all
disks. Remember that Ceph tries to evenly distribute the data.

Regards
-- 
Robert Sander
Heinlein Consulting GmbH
Schwedter Str. 8/9b, 10119 Berlin

http://www.heinlein-support.de

Tel: 030 / 405051-43
Fax: 030 / 405051-19

Zwangsangaben lt. §35a GmbHG:
HRB 93818 B / Amtsgericht Berlin-Charlottenburg,
Geschäftsführer: Peer Heinlein -- Sitz: Berlin

_______________________________________________
ceph-users mailing list -- ceph-users@xxxxxxx
To unsubscribe send an email to ceph-users-leave@xxxxxxx

[Index of Archives]     [Information on CEPH]     [Linux Filesystem Development]     [Ceph Development]     [Ceph Large]     [Ceph Dev]     [Linux USB Development]     [Video for Linux]     [Linux Audio Users]     [Yosemite News]     [Linux Kernel]     [Linux SCSI]     [xfs]


  Powered by Linux