Hi Loic, > The size of each chunk is object size / K. If you have K=1 and M=2 it will > be the same as 3 replicas with none of the advantages ;-) Interesting! I did not see this explained so explicitly. So is the general explanation of k and m something like: k, m: fault tolerance of m+1 replicas, space of 1/k*(m+k) replicas, plus slowness ? So one should never bother with k=1 b/c: k=1, m: fault tolerance of m+1, space of m+1 replicas, plus slowness. (therefore, just use m+1 replicas!) but k=2, m=1: might be useful instead of 2 replicas b/c it has fault tolerance of 2 replicas, space of 1/2*(1+2) = 3/2 = 1.5 replicas, plus slowness. And k=2, m=2: which should be as tolerant as 3 replicas, but take up as much space as (1/2)*(2+2)=2 replicas (right?). Thanks again! Chad. _______________________________________________ ceph-users mailing list ceph-users@xxxxxxxxxxxxxx http://lists.ceph.com/listinfo.cgi/ceph-users-ceph.com
 |