Hi,
Is it possible to achieve redundancy with 2 nodes only?
cephadmin@ceph1:~$ ceph osd tree
# id weight type name up/down reweight
-1 10.88 root default
-2 5.44 host ceph1
0 2.72 osd.0 up 1
1 2.72 osd.1 up 1
-3 5.44 host ceph2
2 2.72 osd.2 up 1
3 2.72 osd.3 up 1
cephadmin@ceph1:~$ ceph status
cluster bce2ff4d-e03b-4b75-9b17-8a48ee4d7788
health HEALTH_OK
monmap e1: 2 mons at
{ceph1=192.168.30.21:6789/0,ceph2=192.168.30.22:6789/0}, election epoch
12, quorum 0,1 ceph1,ceph2
mdsmap e7: 1/1/1 up {0=ceph1=up:active}, 1 up:standby
osdmap e88: 4 osds: 4 up, 4 in
pgmap v2051: 1280 pgs, 5 pools, 13184 MB data, 3328 objects
26457 MB used, 11128 GB / 11158 GB avail
1280 active+clean
I would expect that if I shut down one node, the system will keep
running. But when I tested it, I cannot even execute "ceph status"
command on the running node.
I set "osd_pool_default_size = 2" (min_size=1) on all pools, so I
thought that each copy will reside on each node. Which means that if 1
node goes down the second one will be still operational.
I think my assumptions are wrong, but I could not find the explanation why.
Thanks Jiri
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