On Sun, Apr 21, 2013 at 12:39 AM, Stefan Priebe - Profihost AG <s.priebe@xxxxxxxxxxxx> wrote: > I know it is 100*numofosds/replfactor. But I also read somewhere that it should be a value of 2^X. It this still correct? So for 24 osds and repl 3 100*24/3 => 800 => to be 2^X => 1024? PG counts of 2^x ensure that each PG covers exactly the same amount of hash space. This can improve your distribution, but at reasonable PG counts is definitely not critical — I might use that if I were going to do less than 50 PGs/OSD like you are, but it shouldn't be necessary. -Greg Software Engineer #42 @ http://inktank.com | http://ceph.com _______________________________________________ ceph-users mailing list ceph-users@xxxxxxxxxxxxxx http://lists.ceph.com/listinfo.cgi/ceph-users-ceph.com
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