When ceph_mdsc_build_path is handed a positive dentry, it will return a
zero-length path string with the base set to that dentry. This is not
what we want. Always include at least one path component in the string.
Signed-off-by: Jeff Layton <jlayton@xxxxxxxxxx>
---
fs/ceph/mds_client.c | 3 ++-
1 file changed, 2 insertions(+), 1 deletion(-)
I found this while testing my asynchronous unlink patches. We have
to do the unlink in this case without the parent being locked, and
that showed that we got a bogus path built in this case.
This seems to work correctly, but it's a little unclear whether the
existing behavior is desirable in some cases. Is this the right thing
to do here?
diff --git a/fs/ceph/mds_client.c b/fs/ceph/mds_client.c
index 66eae336a68a..39f5bd2eafda 100644
--- a/fs/ceph/mds_client.c
+++ b/fs/ceph/mds_client.c
@@ -2114,9 +2114,10 @@ char *ceph_mdsc_build_path(struct dentry *dentry, int *plen, u64 *pbase,
if (inode && ceph_snap(inode) == CEPH_SNAPDIR) {
dout("build_path path+%d: %p SNAPDIR\n",
pos, temp);
- } else if (stop_on_nosnap && inode &&
+ } else if (stop_on_nosnap && inode && dentry != temp &&
ceph_snap(inode) == CEPH_NOSNAP) {
spin_unlock(&temp->d_lock);
+ pos++; /* get rid of any prepended '/' */
break;
} else {
pos -= temp->d_name.len;
--
2.21.0
