questions about monmap and command

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Hi

I have 2 questions about monitor.
The test environment contains 3 mon(mona<--leader, monb and monc), 2
mds ,11 osd and ceph v0.26 .

(1)
I killed the cmon process on mona.
Both log and 'ceph mon stat' showed the latest mon's stat(mon.b@1 won
leader election with quorum 1,2).

Then I dump monmap to check, but it didn't record the latest mons' state.
Can someone tell me what the purpose of monmap is?

root@MON2:/mnt/ext4/monb/monmap# ceph mon getmap -o lmonmpa
2011-06-01 07:17:35.669787 mon <- [mon,getmap]
2011-06-01 07:17:35.670964 mon1 -> 'got latest monmap' (0)
2011-06-01 07:17:35.671058 7fa86a776720  wrote 465 byte payload to lmonmpa
root@MON2:/mnt/ext4/monb/monmap# monmaptool --print lmonmpa
monmaptool: monmap file lmonmpa
epoch 1
fsid 73277084-b580-e4f8-da6d-3179bd7a0f0b
last_changed 2011-05-11 11:16:28.730170
created 2011-05-11 11:16:28.730170
0: 192.168.200.181:6789/0 mon.a
1: 192.168.200.182:6789/0 mon.b
2: 192.168.200.183:6789/0 mon.c

(2)
root@MON2:/var/log/ceph# ceph mon stat
2011-06-01 07:21:39.228470 7f3aab8c4710 -- 192.168.200.182:0/14828 >>
192.168.200.181:6789/0 pipe(0x1a70d60 sd=5 pgs=0 cs=0 l=0).fault first
fault
2011-06-01 07:21:45.230389 mon <- [mon,stat]
2011-06-01 07:21:45.230988 mon1 -> 'e1: 3 mons at
{a=192.168.200.181:6789/0,b=192.168.200.182:6789/0,c=192.168.200.183:6789/0},
election epoch 24, quorum 1,2' (0)
                   ^^^^^
What does (0) in the last line mean?



Thanks!
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