On Thu, 2010-07-22 at 17:58 +0000, Joseph L. Casale wrote:
> >What is a program supposed to do to get at "that extra RAM" then ?
> >Just curious ;-)
>
> AFAIK, it must be specifically compiled for it...
---
A PAE enabled Kernel:
NO. It is dependent on the mmap() call in the program as in how the
memory allocation is done in it.
dmesg | grep Memory
Memory: 2070724k/2097024k available (2254k kernel code, 25172k reserved,
1149k data, 272k init, 1179520k highmem)
cat /proc/mtrr
reg00: base=0x00000000 ( 0MB), size=2048MB: write-back, count=1
reg01: base=0xfc000000 (4032MB), size= 64MB: uncachable, count=1
reg02: base=0xfd000000 (4048MB), size= 8MB: write-combining, count=1
Total of Memory Array(s)
Attributes : Total Installed Capacity
Value : 2048 MB
Attributes : Total Installed Capacity Available to the OS
Value : 2024 MB
For as performance wise some would be amazed at what a 32bit machine on
pae can do (prog dependent). Memory allocation is faster than a X86_64.
IE locking spin lock... Don't be confused there is a point to stop and
go 64Bit only.
John
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