On 3/24/2010 3:48 AM, Roland RoLaNd wrote: > > hello, > > i've just wrote the following : > > more ./*.csv | grep -i XXX | echo "Dear XXX, This email is for informative purposes. Your total number of hours for the week of `date` is: `cut -d, -f2` hours Kindly note that the average weekly working hours is : 40." | /usr/sbin/sendEmail -t mail@xxxxxxxxxx -u Test email- disregard it -f othermail@xxxxxxxxxxxxx -s smtp.domain.com:25 > > this looks in a csv file that exists in the same directory for XX and outputs the field right next to it as you notice from : `cut -d, -f2` > > It's working pretty fine for just one user, but i have to do the same for 432 person. and its obviously not as professional as it should be due to the following reasons: > > 1. i have to fill the name for each person in place of XXX as well as their MAIL@xxxxxxxxxx You need to provide more information here. Does each XXX have its own directory (like /home/user)? cd /home for USER in * do ... done Or are the names all in one csv file in another field you can find on the same line as the hours? while read LINE do USER=`cut -d, -f<name_field_number> $LINE` ... done <file.csv > 2. the date command gives the hour as well which is a bit annoying date can give about any format you want with a +format option. > can anyone guide me on how to proceed? > as you notice im a bit of a newbie with bash and im trying my best to improve my one liners/scripts Just remember the perl can do everything the shell can do and much more, so if you run into trouble you can always switch to perl. -- Les Mikesell lesmikesell@xxxxxxxxx _______________________________________________ CentOS mailing list CentOS@xxxxxxxxxx http://lists.centos.org/mailman/listinfo/centos