#!/usr/bin/python
file="test.txt"
fl = open(file,'r')
toParse = fl.readlines()
fl.close()
dublicates = []
firstOne = []
for ln in toParse:
ln=ln.strip()
lnMap = ln.split(':')
target = lnMap[2]
if target in firstOne:
if not target in dublicates:
dublicates.append(target)
else:
firstOne.append(target)
for ln in toParse:
ln = ln.strip()
lnMap = ln.split(':')
target = lnMap[2]
if target in dublicates:
print ln
On Wed, Oct 28, 2009 at 7:09 PM, Truejack <truejack@xxxxxxxxx> wrote:
Need a scripting help to sort out a list and list all the duplicate lines.
My data looks somethings like this
host6:dev406mum.dd.mum.test.com:22:11:11:no
host7:dev258mum.dd.mum.test.com:36:17:19:no
host7:dev258mum.dd.mum.test.com:36:17:19:no
host17:dev258mum.dd.mum.test.com:31:17:19:no
host12:dev258mum.dd.mum.test.com:41:17:19:no
host2:dev258mum.dd.mum.test.com:36:17:19:no
host4:dev258mum.dd.mum.test.com:41:17:19:no
host4:dev258mum.dd.mum.test.com:45:17:19:no
host4:dev258mum.dd.mum.test.com:36:17:19:no
I need to sort this list and print all the lines where column 3 has a duplicate entry.
I need to print the whole line, if a duplicate entry exists in column 3.
I tried using a combination of "sort" and "uniq" but was not successful.
_______________________________________________
CentOS mailing list
CentOS@xxxxxxxxxx
http://lists.centos.org/mailman/listinfo/centos
_______________________________________________ CentOS mailing list CentOS@xxxxxxxxxx http://lists.centos.org/mailman/listinfo/centos
