On Thursday 24 September 2009, Nathan Norton wrote: ... > All 10 drives are 2T in size. ... > # mdadm --create --verbose /dev/md3 --level=6 --raid-devices=10 /dev/sda1 > /dev/sdb1 /dev/sdc1 /dev/sdd1 /dev/sde1 /dev/sdf1 /dev/sdi1 /dev/sdj1 > /dev/sdk1 /dev/sdl1 mdadm: layout defaults to left-symmetric > mdadm: chunk size defaults to 64K > mdadm: size set to 1953511936K > Continue creating array? > > As you can see mdadm sets the size to 1.9T 1953511936K (KiB, 2*2^40) is equal to 2 TB (2*10^12) no mystery here. ... > # mdadm --detail /dev/md3 > /dev/md3: > Version : 0.90 > Creation Time : Thu Sep 24 23:48:32 2009 > Raid Level : raid6 > Array Size : 15628095488 (14904.11 GiB 16003.17 GB) > Used Dev Size : 1953511936 (1863.01 GiB 2000.40 GB) 16003.17 GB (10^9) is exactly what you should get (10 drives -2 for parity times 2 TB). /Peter ... > Anyone got any ideas? > > Nathan
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