What about: perl -ne 'if (/^\s*word/) { print $_; }' logfile any others? On Mon, Jan 5, 2009 at 11:45 AM, Joseph L. Casale <JCasale@xxxxxxxxxxxxxxxxx> wrote: > I need to review a logfile with Sed and cut out all the lines that start with a certain word, problem > is this word begins after some amount of whitespace and unless I search for whitespace at the > beginning followed by "word" I may encounter "word" somewhere legitimately hence why > I don't just search for "word" only... > > Anyone know how to make sed accomplish this? > > Thanks! > jlc > _______________________________________________ > CentOS mailing list > CentOS@xxxxxxxxxx > http://lists.centos.org/mailman/listinfo/centos > -- Thx Joshua Gimer _______________________________________________ CentOS mailing list CentOS@xxxxxxxxxx http://lists.centos.org/mailman/listinfo/centos