On Thu, Nov 27, 2008 at 01:56:11PM -0500, Erick Perez wrote: > So far, cut returns the name up to the space, so in this case it will > return Kimaura and not Kimaura Thomas. No, it doesn't. > # for linia in `cat /etc/passwd` This is your mistake. Think about it for linia in `cat /etc/passwd` do echo Line just read: $linia done That shows what is going wrong; the "in" is splitting at the white space. What you should be doing cat /etc/passwd | while read linia instead. Even better would be while read linia do .... done < /etc/passwd Or, to rewrite the whole program in a one line awk script: awk -F: '{printf("zmprov ma %s@'$domain' displayName %s\n",$1,$5)}' /etc/passwd > $file -- rgds Stephen _______________________________________________ CentOS mailing list CentOS@xxxxxxxxxx http://lists.centos.org/mailman/listinfo/centos