Re: Timeout for a script

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Hi,

On Wed, Nov 12, 2008 at 08:39, Jussi Hirvi <greenspot@xxxxxxxxxxxx> wrote:
> Thanks - but I couldn't make that work as expected. It seems to kill
> *something*, but after that, the rsync part still continues in the
> background...

If what you want to kill is the rsync process, do the opposite, run
rsync in background, sleep for some time, test if it is still running
and then kill it.

> Here's my last test:
>
> log='/root/log/rsync2'
> timeoutseconds=1
> pid=$$
> (sleep $timeoutseconds;
>    echo `date '+%c'` " $0 INTERRUPTED" >>$log;
>    kill -9 $pid) &
> /usr/bin/rsync -avzu --delete /root /home/palvelimet/bckserver1
> echo `date '+%c'` " $0 valmis" >>$log

Use something like:


#! /bin/bash
timeout=60
/usr/bin/rsync -avzu --delete /root /home/palvelimet/bckserver1 &
rsync_pid=$?
sleep "$timeout"
# test if process $rsync_pid is still a child of this process:
ppid_rsync=`ps -o ppid= "$rsync_pid"`
# remove any spaces
ppid_rsync=`echo $ppid_rsync`
# compare the parent of $rsync_pid with this process, if it matches,
kill $rsync_pid
test x"$ppid_rsync" = x"$$" && kill "$rsync_pid"


It's certainly more convoluted than it should be... but it should work.

The C solution is probably the right thing to do, if you have time to
dig into it and find out how it works.

HTH,
Filipe
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