Ok this is kind of a goofy question but I want to make sure I get it right. Suppose we have a 25 mb video, that is 117 seconds long. If we wish for this streaming video to play smoothly with no compression, buffering or skipping, the following bandwidth requirements must be met: 25 megabytes = 204800 kilobits. 204800 kb / 117 seconds ~ 1750kb/s Does that look right to you? _______________________________________________ CentOS mailing list CentOS@xxxxxxxxxx http://lists.centos.org/mailman/listinfo/centos