John wrote:
> > # Here is Subnet number 2. subnet 192.168.0.16 netmask
> > 255.255.255.224 { # Subnet for 29 computers
>
> Isn't this wrong? If the netmask is .224, it should be either
> 192.168.0.0-31 or 192.168.0.32-63. 192.168.0.16 does not make sense
> here.
>
> > On subnet 192.168.0.16 with a mask of 255.255.255.224 will give
> > enuff ips for 29 clients. One for the broadcast addy. Primary subnet
> > would be 192.168.x.x.0 wich can only handle 254 clients. X.16
> > is just taken from that SN and subnetted out into a different
> > allocation block. I slapped it in there hopping the OP would see the
> > that other subnets ways to configure it. Good catch
Yeah, but you cannot really subnet that way:
[angenenr@shutdown ~]$ipcalc.pl 192.168.0.16/255.255.255.224
Address: 192.168.0.16 11000000.10101000.00000000.000 10000
Netmask: 255.255.255.224 = 27 11111111.11111111.11111111.111 00000
Wildcard: 0.0.0.31 00000000.00000000.00000000.000 11111
=>
Network: 192.168.0.0/27 11000000.10101000.00000000.000 00000
HostMin: 192.168.0.1 11000000.10101000.00000000.000 00001
HostMax: 192.168.0.30 11000000.10101000.00000000.000 11110
Broadcast: 192.168.0.31 11000000.10101000.00000000.000 11111
Hosts/Net: 30 Class C, Private Internet
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