Frank M. Ramaekers Jr.
Systems Programmer; MCP, MCP+I, MCSE & RHCE
American Income Life Insurance Company
Phone: (254) 761-6649 Fax: (254) 741-5777
-----Original Message-----
From: centos-bounces@xxxxxxxxxx [mailto:centos-bounces@xxxxxxxxxx] On
Behalf Of Garrick Staples
Sent: Wednesday, May 09, 2007 3:38 PM
To: CentOS mailing list
Subject: Re: Scripting question
On Wed, May 09, 2007 at 03:28:53PM -0500, Frank M. Ramaekers alleged:
> >The first line in your function is only logging its first argument,
not
> >all arguments; and since you pass $line unquoted, the first word is
the
> >first argument.
> >
> >You could either quote $line: ``LogIt "$line"'', or use all arguments
> in
> >LogIt: ``Msg="$@"''.
> >
> >--
> >Garrick Staples, GNU/Linux HPCC SysAdmin
> >University of Southern California
> >
> >09 F9 11 02 9D 74 E3 5B D8 41 56 C5 63 56 88 C0
>
> That makes sense now...I didn't realize the difference...thanks!
So now that that makes sense to you, let me say that you should use both
solutions :)
Quoting $line ensures that special meta-characters aren't expanded. For
example, if $line contained a *, then the shell could expand it with
files in the current directory.
And using $@ instead of $1 in LogIt is just more flexible and is closer
to your actual intention of "log everything I pass on this line."
--
Garrick Staples, GNU/Linux HPCC SysAdmin
University of Southern California
09 F9 11 02 9D 74 E3 5B D8 41 56 C5 63 56 88 C0
---
Thanks, that helps explain it...and I did incorporate both!
Frank M. Ramaekers Jr.
Systems Programmer; MCP, MCP+I, MCSE & RHCE
American Income Life Insurance Company
Phone: (254) 761-6649 Fax: (254) 741-5777
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