On Mon, 20 Mar 2006, James B. Byrne wrote:
> I want a script to determine the owner of a particular file and
> then "sudo -u <thatuserid> <somecomand>". I ran across the --author
> option of ls but that does not seem to give me anything useful. It
> prints a short form of the filename without any other information
> at all. In fact, the output of ls --author is indistinguishable
> from that of ls by itself:
>
>
>> # ls --author htdocs/*
>> htdocs/hlllogo.png
>> # ls htdocs/*
>> htdocs/hlllogo.png
>> #
>
>
> Is there a linux command that will return just the userid in a form
> that can be passed to sudo or do I have to parse ls -l <filename>?
stat -c %U filename
The stat(1) man page has format details; it's part of the coreutils
rpm.
--
Paul Heinlein <> heinlein@xxxxxxxxxx <> www.madboa.com
