On Thursday 09 March 2006 07:12 pm, Nick wrote:
> Running with 1 disk down the array will function at 100% as all the data
> is still available because of the parity info stored on the two good
> disks. The problem is with one disk down you have absolutely no
> redundancy. If one of the other disks failed the data would be lost for
> ever. If you replace the dead disk you can then start rebuilding the
> array so that you get your redundancy back.
>
> this page explains it a lot better than i can
> http://www1.us.dell.com/content/topics/global.aspx/power/en/ps2q03_luse?c=u
>s&l=en&s=corp
Thank you very much Nick. It really gives me a clear understanding.
--
Fajar Priyanto | Reg'd Linux User #327841 | Linux tutorial
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