Sounds like you're pretty constrained if you can't escape $plusmore so alternatives may not be possible either but, if possible, put the contents represented by $plusmore in a file and {read,redirect the output from} the file in myscript. Another option might be to put the contents represented by $plusmore in an environment variable and access that from myscript. The only other option I can think of is to try a different scripting language (awk, perl, tcl, python, you-name-it) to try and get around the issue.
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________________________________________
From: CentOS <centos-bounces@xxxxxxxxxx> on behalf of Anand Buddhdev <anandb@xxxxxxxx>
Sent: Friday, September 28, 2018 8:51 AM
To: CentOS mailing list; Jerry Geis
Subject: [EXTERNAL] Re: Simple bash question
On 28/09/2018 15:39, Jerry Geis wrote:
> I am calling a bash script and passing in somestring that includes a "$"
>
> myscript "$plusmore"
>
> I want to assign in the myscript the $1 arg to something like
> MYTEXT="$1"
>
> when I do that I dont get what I'm expecting. if I do
> MYTEXT='$1'
> I still dont get what I'm expecting.
>
> On the first assignment of MYTEXT I do not want the "$" to be treated as a
> shell variable. I cannot find out how to do that.
>
> I do not have the option of escaping the call to myscipt "\$plusmore". I
> cannot do that.
>
> What am I missing.
You MUST escape the $ in plusmore. If you don't, the calling shell will
try to expand it, and replace it with whatever is in that variable. If
it's not defined, you'll get an empty string. All this happens *before*
myscript is even called.
I'll add that escaping the $ can be done in other ways. Instead of a
backslash, you can also do:
myscript '$plusmore'
Single quotes prevent variable expansion. However, if you are simply
unable to quote $plusmore in some way, then you're stuck.
Anand
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