Re: bash completion in C7

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Hi Gordon,


On Wed, 29 Aug 2018 17:59:58 -0700 Gordon Messmer <gordon.messmer@xxxxxxxxx> wrote:

> On 08/29/2018 09:22 AM, wwp wrote:
> > On Wed, 29 Aug 2018 08:27:06 -0700 Gordon Messmer <gordon.messmer@gmail.c
> om> wrote:  
> >> On 08/28/2018 11:33 PM, wwp wrote:  
> >>>    - it doesn't expand *foo whereas there are *foo-named files in curre  
> nt dir, for instance:
> >>>      # rm *foo
> >>>      will show nothing whereas there's a file barfoo in curdir.  
> >> Tab completion finishes a single word, given a string that appears at th  
> e beginning of a list of candidates.
> > Wrong, tab completion proposes the list of candidates if there are
> > several, and it only finishes a single word automatically if there's
> > only one match for the pattern. At least I never experienced tab
> > completion how you're describing it.  
> 
> Perhaps a miscommunication.  What I mean is that tab completion's final outcome would be a single word, though it can suggest multiple candidates if there are several with matching prefix strings.
> 
> >> Wildcard expansion (Ctrl+x, e) will expand a word containing a wildcard to multiple words on the command line, usually so that you can remove some matches.
> >>
> >> Neither will do specifically what you're trying to do, as far as I know.  
>   I think it's simply too ambiguous.
> > This works fine in CentOS 6  
> 
> $ docker run -i -t --rm centos:6 /bin/bash --login
> [root@9880736fa3ce ~]# touch 1.foo-named
> [root@9880736fa3ce ~]# touch 2.foo-named
> [root@9880736fa3ce ~]# ls *.fo
> 
> Tab completion doesn't work the way you're suggesting, on CentOS 6. It's possible that such a feature exists in some shell, but not one that I'm aware of.

Hah. You may laugh, but talking about mis-communication, you're definitely right.
In my former saying "there are *foo-named files in current dir", I
didn't mean that I had files like:
 1.foo-named
 2.foo-named
but files named like *foo (IOW, maching the pattern *foo), id est:
 1.foo
 2.foo
(my use of "-named" was confusing obviously)
thus, from `ls *foo<TAB>` I was expecting:
 1.foo
 2.foo
I well know that to match "1.foo-named", I should use `ls *foo*<TAB>`
(trailing *) and I'm sure that you know that `ls *foo<TAB>` matches
1.foo.

I think we did now understand each other? ;-) to me, the subject is
over, I've did `complete -r` and voila.


Regards,

-- 
wwp

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