In article <81eb30fb297893749f5c1e211f08c7e4.squirrel@xxxxxxxxxxxxxx>,
<m.roth@xxxxxxxxx> wrote:
> wwp wrote:
> > On Wed, 15 Aug 2012 15:22:10 +0100 Tony Molloy <tony.molloy@xxxxx> wrote:
> >>
> >> I'm looking for a command to extract lines from a large text file, a
> >> password file. A typical user has a username made from a letter
> >> followed by their id-number.
> >>
> >> m9718508:pw:9301:840: Lynch :/home/pgstud/m9718508:/bin/bash
> >>
> >> So for instance if I need to extract lines where;
> >> the 1st field, the username begins with an m
> >> and the 4th field, the group contains exactly 850
> >>
> >> cat passwdfile | grep ^m | grep 850 > output
> >>
> >> is close but fails if the value 850 appears outside the 4th field. In
> >> the above example which should be ignored 850 appears in the username
> >> and home directory and is therefore extracted.
> >
> > Something like `grep -E '^m.+:.*:.*:850:'` maybe?
>
> Complicated.
>
> awk '{ if ($1 ~ /^m/ && $4 == "850" ) { print $0;}}' /etc/passwd
awk -F: '{ if ($1 ~ /^m/ && $4 == "850" ) { print $0;}}' /etc/passwd
Cheers
Tony
--
Tony Mountifield
Work: tony@xxxxxxxxxxxxx - http://www.softins.co.uk
Play: tony@xxxxxxxxxxxxxxx - http://tony.mountifield.org
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