On 08/03/2012 08:54 AM, Lamar Owen wrote: > [For the archives, since I think Johnny just hit the wrong number key.....] > > On Thursday, August 02, 2012 10:24:27 AM Johnny Hughes wrote: >> If you want 8 usable addresses (including the Network number, a gateway >> address, and a Broadcast address), that would mean you need at least 11 >> IPs in that subnet ... the closest fit would be a 255.255.255.240 subnet >> (which has 16 addresses). If you were to want to use th 255.255.255.240 >> subnet, then 192.168.1.48 would not be available as it would the the >> Network number for that subnet ... the usable addresses would be >> 192.168.1.49-63 that case and the Broadcast Address would be 192.168.1.64 > 192.168.1.63 would be the correct broadcast address; .64 would be the network address of the next subnet. Indeed ... Thanks Lamar :-)
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