On Thu, Jul 7, 2011 at 7:48 AM, Helmut Drodofsky <drodofsky@xxxxxxxxxxxxxx> wrote: > I would like to run a program at 2:35 at the first Saturday of each odd > month. > > My solution: > > 35 2 1-7 1,3,5,7,9,11 6 /bin/program > > The program was executed yesterday = Wednesday = day 3, cron ignores the > day of the week! > > Is there a solution with cron – or have I to write a script to check the > date? > > Helmut The most elegant way I have seen to do this is: 35 2 1-7 1,3,5,7,9,11 * [ "$(date '+\%a')" == "Sat" ] && command This will run on the 1st through 7th days of the month, and if the day (as returned by "date +%a") is Sat, then execute the command. Otherwise do nothing. I might also replace the month numbers with names, just to make it easier to understand (though the lines will get long): 35 2 1-7 Jan,Mar,May,Jul,Sep,Nov * [ "$(date '+\%a')" == "Sat" ] && command -☙ Brian Mathis ❧- _______________________________________________ CentOS mailing list CentOS@xxxxxxxxxx http://lists.centos.org/mailman/listinfo/centos