Re: variable in loop

[John Doe <jdmls@xxxxxxxxx>]

From: S Mathias <smathias1972@xxxxxxxxx>

> $ ASDF=hello; a=0; a=$(( 70 - $(echo $ASDF | awk '{print length}') )); echo "$a  
>$ASDF"$(for i in {1..$a}; do printf "."; done)
> 65 hello.
> Why  doesn't it print:
> 65  hello.................................................................
> What  am i missing?

$ for i in {1..3}; do echo $i; done
1
2
3
$ a=3; for i in {1..$a}; do echo $i; done
{1..3}

Try with:
for ((i=1;i<=$a;i++))

JD


      
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